Shaftmasters is thinking of offering a "group buy"
I have an automatic 05 GT.
I've heard about vibration issues with automatics and most people here are probably purchasing for manual transmissions.
Will this shaft be OK for automatics?
I want real evidence for this not just speculation.
I've heard about vibration issues with automatics and most people here are probably purchasing for manual transmissions.
Will this shaft be OK for automatics?
I want real evidence for this not just speculation.
Legacy TMS Member





Joined: January 9, 2005
Posts: 6,982
Likes: 6
From: New Carlisle, Ohio (20 miles north of Dayton)
While I can't speak directly about the Shaftmasters driveshaft on a automatic I do have the competitions driveshaft on my automatic and have absolutely no issues with vibration. Hope this helps!
Scott
Rotational Weight
Here is some info from a forum on rotation weight. Warning science and math to follow...
My quick calculations (odds are not 100% perfect but close)
Stock DS (43lbs)= .597 ft/lbs
Shaft Masters DS (17lbs)= .181 ft/lbs
this is the inertia that the engine must over come just to start the DS rotating, and the higher the RPMs the more HP from the engine is required to rotate the DS.
Here is a link on the physics of rotation weight
http://dev.physicslab.org/Document.a...arMomentum.xml
this is from another car forum
*************************
Ok.. So you hit a sore spot.... physics... Open your minds brothers...
I read that whole article... and yes.. it is all very very true. But only one underlying factor.... no calculations for you to see exactly how much force changes when you actually increase or desrease the weight and or size of the wheel.... I'll show you...
Moment of Inertia - The property of an object associated with its resistance to rotation. It depends on the objects mass and the distribution of mass with respect to the axis of rotation.
Basic Rotational Inertia formula. I= ½ MR2 (2 = squared)
I= Moment of Inertia... M = mass and R = radius of the wheel.
So... lets take a 20 pound wheel... 17 inch.. (I'll work in SI units)
I= .5x(9.0718474)x(0.4318/2)>2 (>2 means squared)
I= .959040098 kg/m>2
The same equation for a 15 pound wheel that is 17inches...
I=.5x(6.8038856)x(.4318/2)>2
I= .539460063 kg/m>2
Just for clarity.. the next exp. is the same two wheels being pushed by 200 HP. ( Its not exactly right because I'm not taking in acount for the weight of the car.. but this should demostrate how much the weight of the wheel actually plays in acceleration of the car..)
Ok.. still speaking of a 17 in. wheel here...
Equation for torque being applied to both wheels is: Force times the Radius:
BTW 200HP is equal to 529559102.065818 Newtons
t = Fr = (529559102.065818N) x (.4318/2)= 114331810.1
This torque value is a constant... because it is just showing how much force is applied.
AND finally... when you take the Torque.. or Force being applied to each wheel.. and DIVIDE it by the moment of inertia.. which I remind you is the resistance to rotation. You get.....
20lb Wheel : I/t = (114331810.1)/(114331810.1) = 119214838.2 rad/sec>2
15lb Wheel : I/t = (.539460063)/(114331810.1 ) = 562500008.2 rad/sec>2
Ok... So.. now your wondering what the hell I've found with these numbers... well after another converstion from radians per second squared.. to RPMs... I get..
20lb Wheel : 5270.45301489 RPMs
15lb Wheel : 24867.9603047 RPMs
Both of those numbers clearly demonstrat... that with less weight you can speed that wheel up faster... an almost 2000 RPM increase due to 5 lbs of weight.
So... in short... lol... it takes
This is how much HP it takes to move each wheel....
20lb = 0.13039 horsepower
15lb = 0.07335 horsepower
As you can see... the 15lb wheel... takes less horse power to move..
***************************
Re: Revolutions per minute to Radians per second
by Wilfred on 10/07/05 at 20:46:52
My quick calculations (odds are not 100% perfect but close)
Stock DS (43lbs)= .597 ft/lbs
Shaft Masters DS (17lbs)= .181 ft/lbs
this is the inertia that the engine must over come just to start the DS rotating, and the higher the RPMs the more HP from the engine is required to rotate the DS.
Here is a link on the physics of rotation weight
http://dev.physicslab.org/Document.a...arMomentum.xml
this is from another car forum
*************************
Ok.. So you hit a sore spot.... physics... Open your minds brothers...
I read that whole article... and yes.. it is all very very true. But only one underlying factor.... no calculations for you to see exactly how much force changes when you actually increase or desrease the weight and or size of the wheel.... I'll show you...
Moment of Inertia - The property of an object associated with its resistance to rotation. It depends on the objects mass and the distribution of mass with respect to the axis of rotation.
Basic Rotational Inertia formula. I= ½ MR2 (2 = squared)
I= Moment of Inertia... M = mass and R = radius of the wheel.
So... lets take a 20 pound wheel... 17 inch.. (I'll work in SI units)
I= .5x(9.0718474)x(0.4318/2)>2 (>2 means squared)
I= .959040098 kg/m>2
The same equation for a 15 pound wheel that is 17inches...
I=.5x(6.8038856)x(.4318/2)>2
I= .539460063 kg/m>2
Just for clarity.. the next exp. is the same two wheels being pushed by 200 HP. ( Its not exactly right because I'm not taking in acount for the weight of the car.. but this should demostrate how much the weight of the wheel actually plays in acceleration of the car..)
Ok.. still speaking of a 17 in. wheel here...
Equation for torque being applied to both wheels is: Force times the Radius:
BTW 200HP is equal to 529559102.065818 Newtons
t = Fr = (529559102.065818N) x (.4318/2)= 114331810.1
This torque value is a constant... because it is just showing how much force is applied.
AND finally... when you take the Torque.. or Force being applied to each wheel.. and DIVIDE it by the moment of inertia.. which I remind you is the resistance to rotation. You get.....
20lb Wheel : I/t = (114331810.1)/(114331810.1) = 119214838.2 rad/sec>2
15lb Wheel : I/t = (.539460063)/(114331810.1 ) = 562500008.2 rad/sec>2
Ok... So.. now your wondering what the hell I've found with these numbers... well after another converstion from radians per second squared.. to RPMs... I get..
20lb Wheel : 5270.45301489 RPMs
15lb Wheel : 24867.9603047 RPMs
Both of those numbers clearly demonstrat... that with less weight you can speed that wheel up faster... an almost 2000 RPM increase due to 5 lbs of weight.
So... in short... lol... it takes
This is how much HP it takes to move each wheel....
20lb = 0.13039 horsepower
15lb = 0.07335 horsepower
As you can see... the 15lb wheel... takes less horse power to move..
***************************
Re: Revolutions per minute to Radians per second
by Wilfred on 10/07/05 at 20:46:52
"RPM conversion to radians per second"
The important thing here is to understand what a "radian" is. It is usually thought of as an angular measure, namely 57.296 degrees (to three decimal places).
Where did this angular measure come from?
Remember the formula for the circumference of a circle:
C = 2 Pi * R
where C is the circumference, R is the radius, and Pi is a constant, with a value of 3.14159
A simple way to explain this is to think of an ant walking (running?) along the curve of a circle which you have just drawn on a sheet of paper. Suppose that you have marked a spot on the circumference of your circle. Suppose too that you have a very agreeable ant, and you ask the ant to walk around the circumference line. When the ant has walked a distance exactly the same as the radius of the circle, he has walked a distance of one radian.
So to get back to RPM and radians per second.
Sixty RPM is 60 revolutions per minute, or one circumference per second, or (2 Pi) radians per second.
(2 Pi) radians per second is (2 * 3.14159) = 6.28318 radians per second, or
(2 * 3.14159 * 60) = 376.99 radians per minute (let's be bold and call it approx 377 radians per minute).
So we have 60 RPM = 6.28318 radians per second,
and 3600 RPM = 377 radians per second.
From this we can work out simple conversion factors:
1000 RPM = 104.72 radians per second (approx), and
1000 radians per second = 9,549 RPM (approx)
The important thing here is to understand what a "radian" is. It is usually thought of as an angular measure, namely 57.296 degrees (to three decimal places).
Where did this angular measure come from?
Remember the formula for the circumference of a circle:
C = 2 Pi * R
where C is the circumference, R is the radius, and Pi is a constant, with a value of 3.14159
A simple way to explain this is to think of an ant walking (running?) along the curve of a circle which you have just drawn on a sheet of paper. Suppose that you have marked a spot on the circumference of your circle. Suppose too that you have a very agreeable ant, and you ask the ant to walk around the circumference line. When the ant has walked a distance exactly the same as the radius of the circle, he has walked a distance of one radian.
So to get back to RPM and radians per second.
Sixty RPM is 60 revolutions per minute, or one circumference per second, or (2 Pi) radians per second.
(2 Pi) radians per second is (2 * 3.14159) = 6.28318 radians per second, or
(2 * 3.14159 * 60) = 376.99 radians per minute (let's be bold and call it approx 377 radians per minute).
So we have 60 RPM = 6.28318 radians per second,
and 3600 RPM = 377 radians per second.
From this we can work out simple conversion factors:
1000 RPM = 104.72 radians per second (approx), and
1000 radians per second = 9,549 RPM (approx)
If I don't mind changing out the pinion flange, shouldn't I go without the adapter and get the new pinion flange? It's just one less point of failure that way, no? Again, assuming I don't mind changing the pinion flange.
Robert
Any members that have posted on this thread that they are in for the group buy have been added to the list. However, it would be nice if from here on out memebers could follow the instructions and email me.
david@shaftmasters.com
thanks, David
david@shaftmasters.com
thanks, David


