5.0 Engine Size Calculation
Not to get to nit-picky:
The area of the cylinder is (I believe): A= (pi)(r^2)
The volume of the cylinder is: V=A*H = (pi)(r^2)(h) which is what I believe you really meant to type
I know its just a small mistake, however, in math there are no small mistakes
You are correct sir. I'm editing my original post to correct the terminology.
OK so when figuring cubes to the gnats ***, the formula described is for the cylinder itself. What about the area in the head (i.e. dome, wedge, hemi...)? That adds in too, right?
It adds into the volume of the interior, but that volume gets ignored when calculating displacement.
It is a well known fact the the old 5.0 was actually a 4.9L. The reason Ford rounded up to 5.0 was not to cause confusion with the 4.9L V6 that was offered in the F100 and F150 trucks.
The March 5.0 article says 92.2 x 92.8mm or 3.263 x 3.647in for 4957cc or 302ci:
http://s42.photobucket.com/albums/e3...t=scan0020.jpg
Do your math thing and report back

Using 2.54 cm per inch, lets try converting each way:
Bore:
92.2mm / 25.4 = 3.6299212598... at 3 decimals rounded, that's 3.630in
3.263in * 25.4 = 82.8802, rounded to 1 decimal, that's 82.9mm
Those numbers are not even remotely close. Obviously an error in the inches figure.
Stroke:
92.8mm / 25.4 = 3.653543... at 3 decimals rounded, that's 3.654in
3.647in * 25.4 = 92.6338, rounded to 1 decimal, that's 92.6mm
Much closer, but still too far off. Again, there is an error in the measurements.
I hope it's the magazine staff and not the Ford engineers who can't get their numbers straight.
Last edited by Skotty; Feb 9, 2010 at 09:15 PM.
Ford's Mustang GT Specs PDF shows bore/stroke as 3.63 in x 3.65 in/92.2 mm x 92.7 mm. It also shows displacement as 302 cu. in./4,951 cc. Either the inch or mm measurements are again rounded, but they do convert properly between each other with rounding unlike the numbers in the magazine article.
In my original post, my 3rd set of calculations just so happened to be calculated with the exact same 3.63 x 3.65. Now lets try 92.2 mm x 92.7 mm:
bore = 92.2 mm = 3.629921... inch
stroke = 92.7 mm = 3.649606... inch
ci = 302.148... which correctly rounds to 302 ci
cc = 4951.325... which correctly rounds to 5.0 L, and also matches the 4951 cc found in the Ford specs PDF.
My guess is the actual unrounded bore and stroke are the metric units shown in the Ford specs PDF, 92.2 mm x 92.7 mm.
The specs PDF can (for now) be found here: http://media.ford.com/images/10031/2...g_GT_Specs.pdf
In my original post, my 3rd set of calculations just so happened to be calculated with the exact same 3.63 x 3.65. Now lets try 92.2 mm x 92.7 mm:
bore = 92.2 mm = 3.629921... inch
stroke = 92.7 mm = 3.649606... inch
ci = 302.148... which correctly rounds to 302 ci
cc = 4951.325... which correctly rounds to 5.0 L, and also matches the 4951 cc found in the Ford specs PDF.
My guess is the actual unrounded bore and stroke are the metric units shown in the Ford specs PDF, 92.2 mm x 92.7 mm.
The specs PDF can (for now) be found here: http://media.ford.com/images/10031/2...g_GT_Specs.pdf
Last edited by Skotty; Feb 12, 2010 at 09:33 PM.
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