Math question
Member
Joined: May 25, 2006
Posts: 37
Likes: 3
Well.
When first learning. It is much easier to put values infront of all variables like a. And all equations have to equal something. In this case Zero because everything is starting on the left side.
1a - 3 + 5a + 2 = 0
Rearrange so all 'a's are on the left of equals and numberical values on the right side of the equals
1a +5a = 3 - 2
Add common variables.
6a = 1
Divide each side by 6.
6a = 1
6 6
a= 1/6
or a= 0.166666666666666667
lol that was fun at 6am. Now! Something much harder.
When first learning. It is much easier to put values infront of all variables like a. And all equations have to equal something. In this case Zero because everything is starting on the left side.
1a - 3 + 5a + 2 = 0
Rearrange so all 'a's are on the left of equals and numberical values on the right side of the equals
1a +5a = 3 - 2
Add common variables.
6a = 1
Divide each side by 6.
6a = 1
6 6
a= 1/6
or a= 0.166666666666666667
lol that was fun at 6am. Now! Something much harder.
x+1-2/x = x+2
1-1/x
1-1/x
Cobra Member
Joined: March 3, 2007
Posts: 1,186
Likes: 0
From: Eden Prairie, MN
Tricky eh?
x+1-2/x=x+2 - multiply by (1-1/x) on both sides which equals
1-1/x
x+1-2/x=x-1+2-2/x
x+1-2/x=x+1-2/x
same on both sides
move x's to one side and numbers to one side.
everything cancels out
0=0
x+1-2/x=x+2 - multiply by (1-1/x) on both sides which equals
1-1/x
x+1-2/x=x-1+2-2/x
x+1-2/x=x+1-2/x
same on both sides
move x's to one side and numbers to one side.
everything cancels out
0=0
Member
Joined: May 25, 2006
Posts: 37
Likes: 3
This is fun. Keep it going. Anyone can figure out calculas.. well. almost. Coming to that its impossible to write out Hard calculas questions. Lets switch the type of thinking. FINITE!! Start ya off with an easy one.
Six new employees, two of whom are married to eachother, are to be assigned six desks that are lined up in a row. If the assignment of employees to desks is made randomly, what is the probability that the married couple will have nonadjacent desks?
Six new employees, two of whom are married to eachother, are to be assigned six desks that are lined up in a row. If the assignment of employees to desks is made randomly, what is the probability that the married couple will have nonadjacent desks?
E=1/2(6x20+5x12) haha beat that smart ppl!!!
Bullitt Member
Joined: July 29, 2005
Posts: 494
Likes: 1
From: Atlanta GA
36x/-12 = (3x+5)*9
-3x = 27x + 45
-30x = 45
x = -45/30
x = -1.5
and to repost the previous question
Six new employees, two of whom are married to each other, are to be assigned six desks that are lined up in a row. If the assignment of employees to desks is made randomly, what is the probability that the married couple will have nonadjacent desks?
-3x = 27x + 45
-30x = 45
x = -45/30
x = -1.5
and to repost the previous question
Six new employees, two of whom are married to each other, are to be assigned six desks that are lined up in a row. If the assignment of employees to desks is made randomly, what is the probability that the married couple will have nonadjacent desks?
how about this?
S = 2 pi r^2 + 2pi r h
S = 2 pi r^2 + 2pi r h
